“The copper as its own key, read through K3's counting rule: key letter for place i is the carved letter at a + b i mod 97”
0002 tested ciphertext autokey, where the key for place i is the carved letter a fixed distance back (i - lag). Here the key is the carved letter at any place given by K3's rule, a + b i mod 97 for every a and b, which includes the copper read backwards (b = -1, a mirror) and every decimation; alone, or with a repeating key of length 1-26 added.
revertedstatus
a new rootparents
30 stime, all phases
0candidates
0/24known letters
unclocked
1
The experiment method
What the method does with the 24 known letters.
A cipher can use its own letters as the keythe secret word The word or string a cipher needs besides the method.. Experiment 2 tried taking the key for each letter from a fixed number of letters earlier. Here the key letter is picked from anywhere in the copper by K3the earlier messages The three solved parts of the sculpture.'s own counting rule: start somewhere, step by a fixed amount, wrap around at 97. That includes reading the copper backwardsa mirror Reading or writing the text from the end to the start., like a mirror. We try every start and step, alone and with a short secret word added, against the 24 known lettersthe known letters Sanborn has confirmed that positions 22 to 34 of the message read EASTNORTHEAST and positions 64 to 74 read BERLINCLOCK..
Words in the margin are defined on the glossary page.
1.1
The method at work
The carved letters go in at the top; the reading comes out at the bottom.
the key
A cipher can take its key from its own letters. Here each letter's key is another carved letter, picked by K3's counting rule: start somewhere, step a fixed amount, wrap at 97. Step 96 reads the copper backwards, like a mirror.
the check
Carved letter minus key letter must give the known letter at all 24 places, or, with a secret word added, the leftovers must repeat with the word's length.
the bound
Every start and step, 16 table rules: at best 7 of 24 alone, as on scrambled coppers (7-9). With a word added nothing shorter than 25 fits, and at 25 K4 has fewer settings than any copper.
2
Best candidate against the known letters
This experiment produced no candidate: the search ruled everything out before a full text was built. Its product is the bounded negative in section 7.
3
Walkthrough, by hand
Redo the method on a few letters with pencil and paper.
Choose a start a = 0 and a step b = 96, which reads the copper backwards: place i takes its key from place 99 - i.
Place 22 (E, carved F) takes its key from place 77, a D.
On the sculpture's alphabet with Vigenere, F minus D must give E; count a hit if it does.
Do this for all 24 known places, every start and step, and every table rule.
With a secret word added, the leftover at each known place must repeat with the word's length.
the worksheet: the first steps by hand, on squared paper
4
Worked example, generated
The same steps run by the code on the real letters.
the copper read backwards as its own key: place i takes its key from place 99 - i (a = 0, b = 96)
sculpture's alphabet, Vigenere
place known carved key place key letter carved - key hit
22 E F 77 D Y no
23 A L 76 G T no
24 S R 75 W T no
25 T V 74 K V no
64 B N 35 O H no
65 E Y 34 S V no
74 K K 25 V T no
5
Hypothesis, for a cryptanalyst
Family, key space, the constraint under test, and the clues it reads.
Scheidt: 'mirrors and obfuscation' (C13), the system 'conveys not only the encrypted data, but also the key' (C6); K3's transposition is the rule i -> 191 + 192 i mod 337 (01-facts.md). Model: p_i = D(c_i, c_{f(i)}) with f(i) = a + b i mod 97, b = 1-96, a = 0-96, f(i) != i for the 24 known places, D the tableau decryption in one of 8 classes (plain and cipher alphabets standard or KRYPTOS; Vigenere, Beaufort, variant; key letters numbered on the cipher alphabet). The key is the copper itself, so every known letter is a check: 24 checks per setting. Second part: p_i = D(c_i, c_{f(i)} + k[i mod L]), L = 1-26; the residual must be periodic, tested by slot agreement. Ten shuffled coppers. 0002's lags are the case b = 1.
6
Prediction
Written before the run; the result decides it.
Alone: no (a, b, class) fits more than 6 of 24 known letters, as on the coppers. With a repeating key: nothing consistent below period 20, counts in the coppers' range. Zero candidates.
7
Method
For each a, b and class, compute the residual r_i = (key value needed at known place i) - (number of c_{f(i)}).
Alone: count known places with r_i = 0.
With a key of length L: residuals sharing slot i mod L must agree.
Repeat on ten shuffled coppers.
Decrypt any full fit.
8
Result and bounds
The harness's record: candidates, gates, loss, and the negative result this experiment leaves behind.
0candidates returned
0passed every gate
0/24known letters, best
–lowest loss
nonechampion before
7,031 maps x 16 rules. Alone: K4 best 7/24, controls [7, 7, 7, 7, 7, 7, 7, 9, 7, 7]; full fits 0. With a periodic key: K4 live below 20: 0; periods outside the control range: [25].
What was searched, as the harness recorded it.
family
the copper as its own key through K3's rule f(i) = a + b i mod 97, alone or plus a periodic key