Experiment 114

“AMSCO, a column shuffle with cells of one and two letters, keyed by any English word, with a repeating key”

AMSCO (A. M. Scott, 1950s ACA) fills a keyed grid with cells that alternate one and two letters, then reads the columns in key order, so letter pairs travel together. It is in none of the route sets. Here every dictionary word giving 3-15 columns keys it, with either cell size first, forward and inverse, with a repeating key of length 1-26 after or before.

revertedstatus
experiment 110parents
8 mintime, all phases
0candidates
0/24known letters
unclocked
1

The experiment method

What the method does with the 24 known letters.

AMSCO is a column shufflea column shuffle Writing the text in rows under a key word and reading the columns in the alphabetical order of the key's letters. in which the grid's boxes hold one letter, then two, then one, alternating, so some pairs of letters stay together when the columns are read out under a secret word. We try every dictionary word as the column word, with a short repeating secret word on the tablethe table The right-hand half of the sculpture, 26 rows of the alphabet each shifted one place further, starting from the word KRYPTOS. before or after, against the 24 known lettersthe known letters Sanborn has confirmed that positions 22 to 34 of the message read EASTNORTHEAST and positions 64 to 74 read BERLINCLOCK..

Words in the margin are defined on the glossary page.

1.1

The method at work

The carved letters go in at the top; the reading comes out at the bottom.

OBKRUOXOGHULBSOLIFBBWEASTNORTHEASTOTWTQSJQSSEKZZWATJKLUDIAWINFBBERLINCLOCKWGDKZXTJCDIGKUHUAUEKCARIN: THE COPPER, ALL 97 LETTERS, THE 24 KNOWN PLACES IN ACCENTAMSCO under SHADOW: cells of one and two letters in turn, each row starting with the other size; columns read in the key's orderSread 5Hread 3Aread 1Dread 2Oread 4Wread 612-345-678-910-111213-141516-17181920-212223-242526-2728-293031-323334-35363738-394041-424344-4546-474849-505152-5354the first six rows of cells (place numbers)column 3 (A) is read first: its cells hold places 4, 13-14, 22 ...place 22 is the third cell's only letter: it comes out 4th, on the copper's REASTNORTHEASTBERLINCLOCKRUOULBWFPQEKLUNFZFDKZGKKwhere each known letter lands, and the carved letter there891,360 routes x 8 tableskey after: period 22 live05the copper: 2period 23 live, above range021the copper: 21period 24 live04,362the copper: 4,184key before: period 25 live0535the copper: 371ten shuffled coppersthe copperOUT: NO READING; ONE EXCESS, AT PERIOD 23, WITHIN CHANCEEASTNORTHEASTBERLINCLOCK
the move

AMSCO writes the message into a grid in cells of one and two letters by turns, then reads the columns in a key word's order. Every dictionary word of 3 to 15 letters is the key here, starting with either cell size.

the check

After the move a repeating secret word on the table must give the copper's letters where the known letters landed; two known letters in one slot of the word must agree.

measured after the run

Period 23 after the move: 21 settings against 1-15, or 15 distinct check sets against 1-9, from obscure key words. Over 52 cells about 4.7 such excesses are expected by chance, so this one is within chance.

2

Best candidate against the known letters

This experiment produced no candidate: the search ruled everything out before a full text was built. Its product is the bounded negative in section 7.

3

Walkthrough, by hand

Redo the method on a few letters with pencil and paper.

  1. Under SHADOW (6 columns), fill the first row with cells of 1, 2, 1, 2, 1, 2 letters, the second with 2, 1, 2, 1, 2, 1, and so on.
  2. Read the columns in the order 3, 4, 2, 5, 1, 6, each column's cells top to bottom.
  3. Each known letter lands at a new place; with a key of length p after the move, letters sharing a slot must agree.
  4. Repeat for every word, first cell size, key length and rule, and with the key before the move.
the worksheet: the first steps by hand, on squared paper
AMSCO UNDER SHADOW, FIRST CELL ONE LETTER: THE CELLS (PLACE NUMBERS), COLUMNS READ IN THE ORDER 3 4 2 5 1 6S5H3A1D2O4W612-345-678-910-111213-141516-17181920-212223-242526-2728-293031-323334-35363738-394041-424344-4546-474849-505152-53545556-575859-606162-6364-656667-686970-71727374-757677-787980-8182-838485-868788-89909192-939495-9697placeletterlands atcopper22E4R23A20B24S21W25T54L64B77DColumn 3 (A) comes first, its cells top tobottom: 4, 13-14, 22, 31-32 ... So place 4 isfirst and place 22 is the 4th letter read.Cells holding a known letter are in accent.
4

Worked example, generated

The same steps run by the code on the real letters.

AMSCO under SHADOW, first cell one letter: the first rows of cells (place numbers)

  1  2-3  4  5-6  7  8-9
  10-11  12  13-14  15  16-17  18
  19  20-21  22  23-24  25  26-27
  28-29  30  31-32  33  34-35  36

columns read in the order [3, 4, 2, 5, 1, 6]
place  letter  lands at  copper there
   22       E         4             R
   23       A        20             B
   24       S        21             W
   25       T        54             L
   64       B        77             D
5

Hypothesis, for a cryptanalyst

Family, key space, the constraint under test, and the clues it reads.

Type 1, a hand route not tested before. AMSCO: rows of w cells holding alternately 1 and 2 letters, each row starting with the other size from the row above, the first cell 1 or 2; columns read in true keyword order (repeats dropped, or the whole word), cells top to bottom; w = 3-15 from every dictionary word; forward and inverse, deduplicated. Key: periodic 1-26 after (slot = carved place mod p) or before, 8 tableau classes, exact by slot agreement. Keeping letter pairs together would also keep some English adjacency, as the width-21 repeats suggest (0018). Ten shuffled coppers.

6

Prediction

Written before the run; the result decides it.

Nothing consistent below period 20; counts inside the coppers' range, give or take one period. Zero candidates.

7

Method

  1. Turn every dictionary word into its column orders of 3-15 columns, each with either first cell size.
  2. Build the move and its inverse; drop repeats.
  3. Test periods 1-26 in both orders and 8 classes.
  4. Count per period on K4 and ten shuffled coppers.
8

Result and bounds

The harness's record: candidates, gates, loss, and the negative result this experiment leaves behind.

0candidates returned
0passed every gate
0/24known letters, best
–lowest loss
nonechampion before

445,680 distinct AMSCO settings from 234,428 words, 891,360 routes x 8 classes x 2 orders, periods 1-26. K4 live below 20: 0. Outside the control range: {'A': [23], 'B': []}.

What was searched, as the harness recorded it.

family
AMSCO (cells of 1 and 2 letters) keyed by every dictionary word of 3-15 columns, then or before a periodic tableau key
words
234,428
distinct key and start settings
445,680
distinct routes
891,360
duplicates skipped
0
periods
1, 26
classes
8
k4 live by period
A
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 2, 21, 4,184, 151, 572
B
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 371, 269,329
controls live by period min
A
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 4,061, 98, 494
B
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 230, 263,011
controls live by period max
A
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 4, 5, 15, 4,362, 170, 593
B
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 16, 535, 289,951
periods outside control range
A
23
B
none
k4 live below 20
none
n k4 live below 20
0
controls
10 shuffled coppers (seed 114), identical search

How this experiment sits among the others is on the lineage page; its family's open hypotheses are on the families page.

Rendered from the record on 2026-10-18 12:26 UTC; updated after every experiment.
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