“F14.1 replication: K4's 5 fitting dictionary alphabet pairs at key length 16 (added form) against 1,000 fresh shuffles, counted as pairs and as distinct cipher alphabets”
Replication only (program.md: a result outside the copies' range is replicated against fresh controls before anything else). 0244's search unchanged, run at key length 16 alone, both forms, on K4 and 1,000 fresh shuffles (seed 245). In 0244 K4 had 5 fitting pairs at 16/added, the 50 copies at most 4; the 5 share two cipher alphabets (AEOLOTROPISM four times), so the count is also taken as distinct cipher alphabets.
In the last test K4the carved letters The 97 letters cut into the copper at the CIA, shown at the top of every experiment page. had slightly more matching alphabet pairs at one key length than any of 50 shuffled copies. That happens by luck now and then when many lengths are looked at, so we count again on 1,000 new shuffles to see how unusual it really is.
Words in the margin are defined on the glossary page.
1.1
The method at work
The carved letters go in at the top; the reading comes out at the bottom.
the idea
Replication of 0244's one unusual count: 5 fitting alphabet pairs on K4 at key length 16, more than any of 50 shuffles.
the check
The same search at length 16 on 1,000 fresh shuffles; counted as pairs and as distinct cipher alphabets.
the bound
p 0.00899 and 0.03796, above the corrected line 0.000962: not a flag. The readings are junk.
2
Experiment lineage
What this experiment was built on, from the lineage page: 8 experiments before it, back to the root of its line. Its number is in bold.
keptreverted, in its family's colour×error or timeoutreverted under today's rulesbuilt on a parent in the same familybuilt on a parent in another family
3
Best candidate against the known letters
Laid out as the copper carries K4: OBKR ends the line that finishes K3, then three lines of 31. Left, as carved, the 24 known places in accent. Right, the candidate: a known place it gets right is an accent cell, one it misses is outlined. This is the candidate with most known letters right; none passed every gate.
in: the copper, always the same
as carved, 97 letters; the 24 known places in accent
ECDMRIPFEIMEHNLSSTTRTVDOHW?OBKR
UOXOGHULBSOLIFBBWFLRVQQPRNGKSSO
TWTQSJQSSEKZZWATJKLUDIAWINFBNYP
VTTMZFPKWGDKZXTJCDIGKUHUAUEKCAR
OBKR ends the line that finishes K3, then three lines of 31
out: the candidate
every place read; known places in accent, misses outlined
ECDMRIPFEIMEHNLSSTTRTVDOHW?KVXC
CXHPKGLNYPWRRYQFBEASTNORTHEASTE
IBHVVNNPTPYTMBJGPLYWHAVISBUCBER
LINCLOCKIHOYTJNLRJRFTDMPDAPYANP
checked: the known letters in place, and the reading turns back into the copper
4
How the score is made
The loss of the best candidate, part by part. Zero is solved.
Known letters missed
0 of 24, ten points each
0.00
English
the 73 free letters score -7.91; English text scores -3.6
4.31
Key
267 bits to write it down (key words are cheap, arbitrary letters 4.7 bits each); each 60 beyond 60 costs a point
3.45
Loss
of 240, the worst possible
7.76 3.2%
5
Walkthrough, by hand
Redo the method on a few letters with pencil and paper.
Take K4 and shuffle its letters, 1,000 times.
For each, file every cipher alphabet by the gaps that key length 16 asks for, and look up every plain alphabet.
Count the matching pairs, and the different cipher alphabets among them.
See how many shuffles reach K4's counts.
the worksheet: the first steps by hand, on squared paper
6
Worked example, generated
The same steps run by the code on the real letters.
Key length 19: known places in the same key slot, and what they ask of the two alphabets (added form)
places known carved the gap on the cipher alphabet must equal the gap on the plain alphabet
26,64 NB QN gap(Q to N) on the cipher alphabet = gap(N to B) on the plain alphabet
27,65 OE QY gap(Q to Y) on the cipher alphabet = gap(O to E) on the plain alphabet
28,66 RR PP gap(P to P) on the cipher alphabet = gap(R to R) on the plain alphabet
29,67 TL RV gap(R to V) on the cipher alphabet = gap(T to L) on the plain alphabet
30,68 HI NT gap(N to T) on the cipher alphabet = gap(H to I) on the plain alphabet
31,69 EN GT gap(G to T) on the cipher alphabet = gap(E to N) on the plain alphabet
32,70 AC KM gap(K to M) on the cipher alphabet = gap(A to C) on the plain alphabet
33,71 SL SZ gap(S to Z) on the cipher alphabet = gap(S to L) on the plain alphabet
34,72 TO SF gap(S to F) on the cipher alphabet = gap(T to O) on the plain alphabet
Every cipher alphabet is filed by its gaps; every plain alphabet looks up the gaps it needs.
7
Hypothesis, for a cryptanalyst
Family, key space, the constraint under test, and the clues it reads.
F14.1 (0244): two dictionary keyword alphabets with a free periodic key, exact. One of 52 (length, form) cells had K4 above all 50 copies in its fit count (5 against 4), with readings below the copies' best by English (-7.91 against -7.63). Pre-registered: the cell flags only if K4's count is reached by fewer than 5% of 1,000 fresh shuffles after the 52-cell correction, p < 0.05/52 = 0.00096, on either count.
8
Prediction
Written before the run; the result decides it.
Several percent of fresh shuffles reach 5 or more pairs at 16/added: p well above 0.001, not a flag.
9
Method
0244's index search at key length 16, both forms, no key-word step needed (16-letter keys are fully forced).
K4 and 1,000 fresh shuffles; per text the number of fitting pairs and of distinct cipher alphabets among them.
p = (1 + shuffles at or above K4) / 1,001, per count; flag below 0.00096.
10
Result and bounds
The harness's record: candidates, gates, loss, and the negative result this experiment leaves behind.
5candidates returned
0passed every gate
24/24known letters, best
3.2%lowest loss
nonechampion before
All 5 candidates, lowest loss first.
1failed at resubmitted24/24 known lettersloss 3.2%
ECDMRIPFEIMEHNLSSTTRTVDOHW?KVXC
CXHPKGLNYPWRRYQFBEASTNORTHEASTE
IBHVVNNPTPYTMBJGPLYWHAVISBUCBER
LINCLOCKIHOYTJNLRJRFTDMPDAPYANP
2failed at resubmitted24/24 known lettersloss 3.3%
ECDMRIPFEIMEHNLSSTTRTVDOHW?KVXC
CXZPKHLNYOWRRYQFBEASTNORTHEASTE
IBZVVNNPTPFTMBJHPLYWZAVISBACBER
LINCLOCKIZOFTJNLRJRFTDMPDAPFANP
3failed at resubmitted24/24 known lettersloss 3.3%
ECDMRIPFEIMEHNLSSTTRTVDOHW?KVXC
CXZPKHLNYOWRRYQFBEASTNORTHEASTE
IBZVVNNPTPFTMBJHPLYWZAVISBACBER
LINCLOCKIZOFTJNLRJRFTDMPDAPFANP
4failed at resubmitted24/24 known lettersloss 3.4%
ECDMRIPFEIMEHNLSSTTRTVDOHW?JVXC
AXPNJHLMZLWRRZQFDEASTNORTHEASTE
IDPVVMNNTNGTKBHGNYZWPAWISBBCBER
LINCLOCKIPOGTHMLRHSFTDKQDANGAMN
5failed at resubmitted24/24 known lettersloss 3.5%
ECDMRIPFEIMEHNLSSTTRTVDOHW?CGBD
EWKNHHYPZKVEOJYGFEASTNORTHEASTT
IFZBBKNCTVFSMVFVMYJGLZAICEDIBER
LINCLOCKIKMFSLRMROKBDFJQNUVFDZI
16/added: K4 5 pairs (2 cipher alphabets), p 0.00899 / 0.03796 against 1000 fresh shuffles; flag False